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5433100325114 = 271135279872241
BaseRepresentation
bin100111100001111111000…
…0000111101000011111010
3201020101210002210020022012
41033003332000331003322
51203003442140400424
615315533135325522
71100346201532550
oct117037600750372
921211702706265
105433100325114
11180518a547050
12738b7a3808a2
133054541a76a7
1414ad6ba33bd0
15964da003b0e
hex4f0fe03d0fa

5433100325114 has 16 divisors (see below), whose sum is σ = 10160603205696. Its totient is φ = 2116792334400.

The previous prime is 5433100325113. The next prime is 5433100325153. The reversal of 5433100325114 is 4115230013345.

It is a super-2 number, since 2×54331003251142 (a number of 26 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (5433100325113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17639935967 + ... + 17639936274.

It is an arithmetic number, because the mean of its divisors is an integer number (635037700356).

Almost surely, 25433100325114 is an apocalyptic number.

5433100325114 is a deficient number, since it is larger than the sum of its proper divisors (4727502880582).

5433100325114 is a wasteful number, since it uses less digits than its factorization.

5433100325114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35279872261.

The product of its (nonzero) digits is 21600, while the sum is 32.

Adding to 5433100325114 its reverse (4115230013345), we get a palindrome (9548330338459).

The spelling of 5433100325114 in words is "five trillion, four hundred thirty-three billion, one hundred million, three hundred twenty-five thousand, one hundred fourteen".

Divisors: 1 2 7 11 14 22 77 154 35279872241 70559744482 246959105687 388078594651 493918211374 776157189302 2716550162557 5433100325114