543320023345 has 64 divisors (see below), whose sum is σ = 734885498880. Its totient is φ = 382249324800.

The previous prime is 543320023321. The next prime is 543320023361.

543320023345 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 543320023345 - 2⁵ = 543320023313 is a prime.

It is a super-2 number, since 2×543320023345² (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 543320023345.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 141230212 + ... + 141234058.

It is an arithmetic number, because the mean of its divisors is an integer number (11482585920).

Almost surely, 2^543320023345 is an apocalyptic number.

543320023345 is a gapful number since it is divisible by the number (55) formed by its first and last digit.

It is an amenable number.

543320023345 is a deficient number, since it is larger than the sum of its proper divisors (191565475535).

543320023345 is a wasteful number, since it uses less digits than its factorization.

543320023345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4606.

The product of its (nonzero) digits is 129600, while the sum is 34.

It can be divided in two parts, 5433200 and 23345, that added together give a palindrome (5456545).

The spelling of 543320023345 in words is "five hundred forty-three billion, three hundred twenty million, twenty-three thousand, three hundred forty-five".