Base | Representation |
---|---|
bin | 100111100010000010100… |
… | …1110011111101101010011 |
3 | 201020102002112110011210022 |
4 | 1033010011032133231103 |
5 | 1203004214124043121 |
6 | 15315553140454055 |
7 | 1100352201120131 |
oct | 117040516375523 |
9 | 21212075404708 |
10 | 5433221315411 |
11 | 180524187492a |
12 | 738bb29aa32b |
13 | 30547328a296 |
14 | 14ad7db2a751 |
15 | 964e5952aab |
hex | 4f10539fb53 |
5433221315411 has 2 divisors, whose sum is σ = 5433221315412. Its totient is φ = 5433221315410.
The previous prime is 5433221315387. The next prime is 5433221315477. The reversal of 5433221315411 is 1145131223345.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5433221315411 is a prime.
It is not a weakly prime, because it can be changed into another prime (5433221317411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2716610657705 + 2716610657706.
It is an arithmetic number, because the mean of its divisors is an integer number (2716610657706).
Almost surely, 25433221315411 is an apocalyptic number.
5433221315411 is a deficient number, since it is larger than the sum of its proper divisors (1).
5433221315411 is an equidigital number, since it uses as much as digits as its factorization.
5433221315411 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 43200, while the sum is 35.
Adding to 5433221315411 its reverse (1145131223345), we get a palindrome (6578352538756).
The spelling of 5433221315411 in words is "five trillion, four hundred thirty-three billion, two hundred twenty-one million, three hundred fifteen thousand, four hundred eleven".
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