Base | Representation |
---|---|
bin | 11000101101011000110000… |
… | …11011110110000001010011 |
3 | 21010101110211010200100220012 |
4 | 30112230120123312001103 |
5 | 24110220203022322120 |
6 | 311321344400505135 |
7 | 14305435516546430 |
oct | 1426543033660123 |
9 | 233343733610805 |
10 | 54336041214035 |
11 | 16349870800559 |
12 | 611683231b1ab |
13 | 2441b361ab459 |
14 | d5bc42590b87 |
15 | 64361247c1c5 |
hex | 316b186f6053 |
54336041214035 has 32 divisors (see below), whose sum is σ = 75175548567552. Its totient is φ = 36930778174080.
The previous prime is 54336041214031. The next prime is 54336041214083. The reversal of 54336041214035 is 53041214063345.
It is a happy number.
It is not a de Polignac number, because 54336041214035 - 22 = 54336041214031 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 54336041213983 and 54336041214001.
It is not an unprimeable number, because it can be changed into a prime (54336041214031) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1044497 + ... + 10476786.
It is an arithmetic number, because the mean of its divisors is an integer number (2349235892736).
Almost surely, 254336041214035 is an apocalyptic number.
54336041214035 is a deficient number, since it is larger than the sum of its proper divisors (20839507353517).
54336041214035 is a wasteful number, since it uses less digits than its factorization.
54336041214035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11522483.
The product of its (nonzero) digits is 518400, while the sum is 41.
The spelling of 54336041214035 in words is "fifty-four trillion, three hundred thirty-six billion, forty-one million, two hundred fourteen thousand, thirty-five".
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