Base | Representation |
---|---|
bin | 11000101101011001101011… |
… | …10011110010111110010001 |
3 | 21010101112002111000010102112 |
4 | 30112230311303302332101 |
5 | 24110222210203013043 |
6 | 311321505323355105 |
7 | 14305453652462333 |
oct | 1426546563627621 |
9 | 233345074003375 |
10 | 54336534032273 |
11 | 16349aa3a02159 |
12 | 611694b382a95 |
13 | 2441bb431a68c |
14 | d5bc8bbd7453 |
15 | 643640877518 |
hex | 316b35cf2f91 |
54336534032273 has 2 divisors, whose sum is σ = 54336534032274. Its totient is φ = 54336534032272.
The previous prime is 54336534032257. The next prime is 54336534032321. The reversal of 54336534032273 is 37223043563345.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 41040833441344 + 13295700590929 = 6406312^2 + 3646327^2 .
It is a cyclic number.
It is not a de Polignac number, because 54336534032273 - 24 = 54336534032257 is a prime.
It is not a weakly prime, because it can be changed into another prime (54336534032173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27168267016136 + 27168267016137.
It is an arithmetic number, because the mean of its divisors is an integer number (27168267016137).
Almost surely, 254336534032273 is an apocalyptic number.
It is an amenable number.
54336534032273 is a deficient number, since it is larger than the sum of its proper divisors (1).
54336534032273 is an equidigital number, since it uses as much as digits as its factorization.
54336534032273 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16329600, while the sum is 50.
The spelling of 54336534032273 in words is "fifty-four trillion, three hundred thirty-six billion, five hundred thirty-four million, thirty-two thousand, two hundred seventy-three".
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