Base | Representation |
---|---|
bin | 11000101101011001101011… |
… | …10011110101011010101001 |
3 | 21010101112002111000122011012 |
4 | 30112230311303311122221 |
5 | 24110222210203323111 |
6 | 311321505323513305 |
7 | 14305453652533451 |
oct | 1426546563653251 |
9 | 233345074018135 |
10 | 54336534042281 |
11 | 16349aa3a09727 |
12 | 611694b388835 |
13 | 2441bb43220ba |
14 | d5bc8bbdad61 |
15 | 64364087a48b |
hex | 316b35cf56a9 |
54336534042281 has 2 divisors, whose sum is σ = 54336534042282. Its totient is φ = 54336534042280.
The previous prime is 54336534042191. The next prime is 54336534042317. The reversal of 54336534042281 is 18224043563345.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 53788069381225 + 548464661056 = 7334035^2 + 740584^2 .
It is a cyclic number.
It is not a de Polignac number, because 54336534042281 - 238 = 54061656135337 is a prime.
It is a super-2 number, since 2×543365340422812 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (54336539042281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27168267021140 + 27168267021141.
It is an arithmetic number, because the mean of its divisors is an integer number (27168267021141).
Almost surely, 254336534042281 is an apocalyptic number.
It is an amenable number.
54336534042281 is a deficient number, since it is larger than the sum of its proper divisors (1).
54336534042281 is an equidigital number, since it uses as much as digits as its factorization.
54336534042281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8294400, while the sum is 50.
The spelling of 54336534042281 in words is "fifty-four trillion, three hundred thirty-six billion, five hundred thirty-four million, forty-two thousand, two hundred eighty-one".
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