Base | Representation |
---|---|
bin | 100111100010010111110… |
… | …0100000001001100111001 |
3 | 201020110221000222102000202 |
4 | 1033010233210001030321 |
5 | 1203012142442210242 |
6 | 15320151432411545 |
7 | 1100405614336535 |
oct | 117045744011471 |
9 | 21213830872022 |
10 | 5433931600697 |
11 | 18055767a9766 |
12 | 739170846bb5 |
13 | 30555748b032 |
14 | 14b00a1c0bc5 |
15 | 96537ea7932 |
hex | 4f12f901339 |
5433931600697 has 2 divisors, whose sum is σ = 5433931600698. Its totient is φ = 5433931600696.
The previous prime is 5433931600421. The next prime is 5433931600733. The reversal of 5433931600697 is 7960061393345.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2765449265296 + 2668482335401 = 1662964^2 + 1633549^2 .
It is a cyclic number.
It is not a de Polignac number, because 5433931600697 - 210 = 5433931599673 is a prime.
It is a super-2 number, since 2×54339316006972 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5433931620697) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2716965800348 + 2716965800349.
It is an arithmetic number, because the mean of its divisors is an integer number (2716965800349).
Almost surely, 25433931600697 is an apocalyptic number.
It is an amenable number.
5433931600697 is a deficient number, since it is larger than the sum of its proper divisors (1).
5433931600697 is an equidigital number, since it uses as much as digits as its factorization.
5433931600697 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11022480, while the sum is 56.
The spelling of 5433931600697 in words is "five trillion, four hundred thirty-three billion, nine hundred thirty-one million, six hundred thousand, six hundred ninety-seven".
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