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543401330523169 is a prime number
BaseRepresentation
bin111101110001110000111101…
…1010001101011110000100001
32122021000122211000221212211211
41323203201323101223300201
51032211041411103220134
65203415042555310121
7222313310353445026
oct17343417321536041
92567018730855754
10543401330523169
11148165234700738
1250b4299a14b341
131a4296aa9607a1
149828a9c5b954d
1542c51b0476764
hex1ee387b46bc21

543401330523169 has 2 divisors, whose sum is σ = 543401330523170. Its totient is φ = 543401330523168.

The previous prime is 543401330523143. The next prime is 543401330523179. The reversal of 543401330523169 is 961325033104345.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 501907313210944 + 41494017312225 = 22403288^2 + 6441585^2 .

It is a cyclic number.

It is not a de Polignac number, because 543401330523169 - 25 = 543401330523137 is a prime.

It is a super-2 number, since 2×5434013305231692 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (543401330523179) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271700665261584 + 271700665261585.

It is an arithmetic number, because the mean of its divisors is an integer number (271700665261585).

Almost surely, 2543401330523169 is an apocalyptic number.

It is an amenable number.

543401330523169 is a deficient number, since it is larger than the sum of its proper divisors (1).

543401330523169 is an equidigital number, since it uses as much as digits as its factorization.

543401330523169 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3499200, while the sum is 49.

The spelling of 543401330523169 in words is "five hundred forty-three trillion, four hundred one billion, three hundred thirty million, five hundred twenty-three thousand, one hundred sixty-nine".