Base | Representation |
---|---|
bin | 100111100010011100111… |
… | …0111010000001110010001 |
3 | 201020111101002011021211222 |
4 | 1033010321313100032101 |
5 | 1203013021212240441 |
6 | 15320220524414425 |
7 | 1100413113256634 |
oct | 117047167201621 |
9 | 21214332137758 |
10 | 5434104415121 |
11 | 18056553037a8 |
12 | 7391ba6a7415 |
13 | 3055842173a5 |
14 | 14b025127c1b |
15 | 96548241d4b |
hex | 4f139dd0391 |
5434104415121 has 2 divisors, whose sum is σ = 5434104415122. Its totient is φ = 5434104415120.
The previous prime is 5434104415109. The next prime is 5434104415247. The reversal of 5434104415121 is 1215144014345.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5103370156096 + 330734259025 = 2259064^2 + 575095^2 .
It is a cyclic number.
It is not a de Polignac number, because 5434104415121 - 218 = 5434104152977 is a prime.
It is not a weakly prime, because it can be changed into another prime (5434104415921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2717052207560 + 2717052207561.
It is an arithmetic number, because the mean of its divisors is an integer number (2717052207561).
Almost surely, 25434104415121 is an apocalyptic number.
It is an amenable number.
5434104415121 is a deficient number, since it is larger than the sum of its proper divisors (1).
5434104415121 is an equidigital number, since it uses as much as digits as its factorization.
5434104415121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 38400, while the sum is 35.
Adding to 5434104415121 its reverse (1215144014345), we get a palindrome (6649248429466).
The spelling of 5434104415121 in words is "five trillion, four hundred thirty-four billion, one hundred four million, four hundred fifteen thousand, one hundred twenty-one".
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