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54343312301 = 97560240333
BaseRepresentation
bin110010100111000111…
…010010001110101101
312012021021112022000102
4302213013102032231
51342243341443201
640544233440445
73632451350555
oct624707221655
9165237468012
1054343312301
1121057423953
12a647570125
1351808455c5
1428b74d0165
151630d3226b
hexca71d23ad

54343312301 has 4 divisors (see below), whose sum is σ = 54903552732. Its totient is φ = 53783071872.

The previous prime is 54343312277. The next prime is 54343312393. The reversal of 54343312301 is 10321334345.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 23779182025 + 30564130276 = 154205^2 + 174826^2 .

It is a cyclic number.

It is not a de Polignac number, because 54343312301 - 222 = 54339117997 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54343302301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 280120070 + ... + 280120263.

It is an arithmetic number, because the mean of its divisors is an integer number (13725888183).

Almost surely, 254343312301 is an apocalyptic number.

It is an amenable number.

54343312301 is a deficient number, since it is larger than the sum of its proper divisors (560240431).

54343312301 is an equidigital number, since it uses as much as digits as its factorization.

54343312301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 560240430.

The product of its (nonzero) digits is 12960, while the sum is 29.

Adding to 54343312301 its reverse (10321334345), we get a palindrome (64664646646).

The spelling of 54343312301 in words is "fifty-four billion, three hundred forty-three million, three hundred twelve thousand, three hundred one".

Divisors: 1 97 560240333 54343312301