Base | Representation |
---|---|
bin | 1010001000000100… |
… | …11000011001100101 |
3 | 112000212121212201121 |
4 | 11010002120121211 |
5 | 42113212122323 |
6 | 2255241453541 |
7 | 251501665516 |
oct | 50402303145 |
9 | 15025555647 |
10 | 5436442213 |
11 | 233a803554 |
12 | 10787a12b1 |
13 | 6883bc517 |
14 | 398030a0d |
15 | 21c417a5d |
hex | 144098665 |
5436442213 has 4 divisors (see below), whose sum is σ = 5436593568. Its totient is φ = 5436290860.
The previous prime is 5436442199. The next prime is 5436442217. The reversal of 5436442213 is 3122446345.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 5436442213 - 25 = 5436442181 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5436442217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12270 + ... + 104992.
It is an arithmetic number, because the mean of its divisors is an integer number (1359148392).
Almost surely, 25436442213 is an apocalyptic number.
It is an amenable number.
5436442213 is a deficient number, since it is larger than the sum of its proper divisors (151355).
5436442213 is an equidigital number, since it uses as much as digits as its factorization.
5436442213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 151354.
The product of its digits is 69120, while the sum is 34.
The square root of 5436442213 is about 73732.2332023112. The cubic root of 5436442213 is about 1758.3483787926.
Adding to 5436442213 its reverse (3122446345), we get a palindrome (8558888558).
The spelling of 5436442213 in words is "five billion, four hundred thirty-six million, four hundred forty-two thousand, two hundred thirteen".
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