Base | Representation |
---|---|
bin | 100111100101010000100… |
… | …1001100101111100000001 |
3 | 201021001221011120200110211 |
4 | 1033022201021211330001 |
5 | 1203112342323240301 |
6 | 15323055013554121 |
7 | 1101015356046505 |
oct | 117124111457401 |
9 | 21231834520424 |
10 | 5440132243201 |
11 | 18081689111a7 |
12 | 73a401345941 |
13 | 306004ca7676 |
14 | 14b4378dc305 |
15 | 9679c525051 |
hex | 4f2a1265f01 |
5440132243201 has 2 divisors, whose sum is σ = 5440132243202. Its totient is φ = 5440132243200.
The previous prime is 5440132243181. The next prime is 5440132243207. The reversal of 5440132243201 is 1023422310445.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5222207596225 + 217924646976 = 2285215^2 + 466824^2 .
It is a cyclic number.
It is not a de Polignac number, because 5440132243201 - 29 = 5440132242689 is a prime.
It is not a weakly prime, because it can be changed into another prime (5440132243207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2720066121600 + 2720066121601.
It is an arithmetic number, because the mean of its divisors is an integer number (2720066121601).
Almost surely, 25440132243201 is an apocalyptic number.
It is an amenable number.
5440132243201 is a deficient number, since it is larger than the sum of its proper divisors (1).
5440132243201 is an equidigital number, since it uses as much as digits as its factorization.
5440132243201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 5440132243201 its reverse (1023422310445), we get a palindrome (6463554553646).
The spelling of 5440132243201 in words is "five trillion, four hundred forty billion, one hundred thirty-two million, two hundred forty-three thousand, two hundred one".
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