Base | Representation |
---|---|
bin | 110010101010110010… |
… | …101101000011001001 |
3 | 12012102120122200021201 |
4 | 302222302231003021 |
5 | 1342410141312433 |
6 | 40554320304201 |
7 | 3634131043063 |
oct | 625262550311 |
9 | 165376580251 |
10 | 54405025993 |
11 | 210892452aa |
12 | a664172061 |
13 | 5190572596 |
14 | 28c1796733 |
15 | 1636472a7d |
hex | caacad0c9 |
54405025993 has 2 divisors, whose sum is σ = 54405025994. Its totient is φ = 54405025992.
The previous prime is 54405025981. The next prime is 54405026023. The reversal of 54405025993 is 39952050445.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 37084360329 + 17320665664 = 192573^2 + 131608^2 .
It is a cyclic number.
It is not a de Polignac number, because 54405025993 - 213 = 54405017801 is a prime.
It is not a weakly prime, because it can be changed into another prime (54405025903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27202512996 + 27202512997.
It is an arithmetic number, because the mean of its divisors is an integer number (27202512997).
Almost surely, 254405025993 is an apocalyptic number.
It is an amenable number.
54405025993 is a deficient number, since it is larger than the sum of its proper divisors (1).
54405025993 is an equidigital number, since it uses as much as digits as its factorization.
54405025993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972000, while the sum is 46.
The spelling of 54405025993 in words is "fifty-four billion, four hundred five million, twenty-five thousand, nine hundred ninety-three".
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