Base | Representation |
---|---|
bin | 11000101111100010100110… |
… | …10110100110000100001011 |
3 | 21010122112211112020101210021 |
4 | 30113301103112212010023 |
5 | 24112423232244401424 |
6 | 311415343524201311 |
7 | 14313665421200533 |
oct | 1427612326460413 |
9 | 233575745211707 |
10 | 54410044137739 |
11 | 163781964a3434 |
12 | 6129045839237 |
13 | 2448acaa2c1c4 |
14 | d61662a7c4c3 |
15 | 6454e41de4e4 |
hex | 317c535a610b |
54410044137739 has 2 divisors, whose sum is σ = 54410044137740. Its totient is φ = 54410044137738.
The previous prime is 54410044137733. The next prime is 54410044137817. The reversal of 54410044137739 is 93773144001445.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54410044137739 - 25 = 54410044137707 is a prime.
It is a super-2 number, since 2×544100441377392 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (54410044137733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27205022068869 + 27205022068870.
It is an arithmetic number, because the mean of its divisors is an integer number (27205022068870).
Almost surely, 254410044137739 is an apocalyptic number.
54410044137739 is a deficient number, since it is larger than the sum of its proper divisors (1).
54410044137739 is an equidigital number, since it uses as much as digits as its factorization.
54410044137739 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5080320, while the sum is 52.
The spelling of 54410044137739 in words is "fifty-four trillion, four hundred ten billion, forty-four million, one hundred thirty-seven thousand, seven hundred thirty-nine".
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