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5441020655153 is a prime number
BaseRepresentation
bin100111100101101011000…
…0110100111011000110001
3201021011020002021200120012
41033023112012213120301
51203121202241431103
615323323111424305
71101046364323016
oct117132606473061
921234202250505
105441020655153
111808584349256
1273a60a985095
13306117074705
1414b4bd8bd70d
15968005132d8
hex4f2d61a7631

5441020655153 has 2 divisors, whose sum is σ = 5441020655154. Its totient is φ = 5441020655152.

The previous prime is 5441020655089. The next prime is 5441020655159. The reversal of 5441020655153 is 3515560201445.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5425810859569 + 15209795584 = 2329337^2 + 123328^2 .

It is a cyclic number.

It is not a de Polignac number, because 5441020655153 - 26 = 5441020655089 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 5441020655153.

It is not a weakly prime, because it can be changed into another prime (5441020655159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2720510327576 + 2720510327577.

It is an arithmetic number, because the mean of its divisors is an integer number (2720510327577).

Almost surely, 25441020655153 is an apocalyptic number.

It is an amenable number.

5441020655153 is a deficient number, since it is larger than the sum of its proper divisors (1).

5441020655153 is an equidigital number, since it uses as much as digits as its factorization.

5441020655153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 360000, while the sum is 41.

Adding to 5441020655153 its reverse (3515560201445), we get a palindrome (8956580856598).

The spelling of 5441020655153 in words is "five trillion, four hundred forty-one billion, twenty million, six hundred fifty-five thousand, one hundred fifty-three".