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54411339060977 is a prime number
BaseRepresentation
bin11000101111100101000001…
…00010010101011011110001
321010122200011202212022112012
430113302200202111123301
524112433410244422402
6311420120223012305
714314042463645123
oct1427624042253361
9233580152768465
1054411339060977
11163787a0443428
12612934743a095
132448c760aa482
14d61746a3b213
1564556cc2a452
hex317ca08956f1

54411339060977 has 2 divisors, whose sum is σ = 54411339060978. Its totient is φ = 54411339060976.

The previous prime is 54411339060959. The next prime is 54411339060997. The reversal of 54411339060977 is 77906093311445.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 30468236198416 + 23943102862561 = 5519804^2 + 4893169^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-54411339060977 is a prime.

It is not a weakly prime, because it can be changed into another prime (54411339060907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27205669530488 + 27205669530489.

It is an arithmetic number, because the mean of its divisors is an integer number (27205669530489).

Almost surely, 254411339060977 is an apocalyptic number.

It is an amenable number.

54411339060977 is a deficient number, since it is larger than the sum of its proper divisors (1).

54411339060977 is an equidigital number, since it uses as much as digits as its factorization.

54411339060977 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17146080, while the sum is 59.

The spelling of 54411339060977 in words is "fifty-four trillion, four hundred eleven billion, three hundred thirty-nine million, sixty thousand, nine hundred seventy-seven".