Base | Representation |
---|---|
bin | 11000101111101000101001… |
… | …10001100100010011010011 |
3 | 21010122212012200102012120012 |
4 | 30113310110301210103103 |
5 | 24113001404014223331 |
6 | 311421041525305135 |
7 | 14314142013646016 |
oct | 1427642461442323 |
9 | 233585180365505 |
10 | 54413289211091 |
11 | 16379601232038 |
12 | 61297b05651ab |
13 | 24491c711c855 |
14 | d6188da3b37d |
15 | 64563404282b |
hex | 317d14c644d3 |
54413289211091 has 2 divisors, whose sum is σ = 54413289211092. Its totient is φ = 54413289211090.
The previous prime is 54413289211019. The next prime is 54413289211097. The reversal of 54413289211091 is 19011298231445.
Together with previous prime (54413289211019) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54413289211091 - 214 = 54413289194707 is a prime.
It is not a weakly prime, because it can be changed into another prime (54413289211097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27206644605545 + 27206644605546.
It is an arithmetic number, because the mean of its divisors is an integer number (27206644605546).
Almost surely, 254413289211091 is an apocalyptic number.
54413289211091 is a deficient number, since it is larger than the sum of its proper divisors (1).
54413289211091 is an equidigital number, since it uses as much as digits as its factorization.
54413289211091 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 622080, while the sum is 50.
The spelling of 54413289211091 in words is "fifty-four trillion, four hundred thirteen billion, two hundred eighty-nine million, two hundred eleven thousand, ninety-one".
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