Base | Representation |
---|---|
bin | 110010101011011000… |
… | …111100101010110101 |
3 | 12012110021112000121202 |
4 | 302223120330222311 |
5 | 1342420223121240 |
6 | 40555315222245 |
7 | 3634312206566 |
oct | 625330745265 |
9 | 165407460552 |
10 | 54415051445 |
11 | 210939725a7 |
12 | a6675a7985 |
13 | 51926728c1 |
14 | 28c2c4616d |
15 | 16372a3315 |
hex | cab63cab5 |
54415051445 has 16 divisors (see below), whose sum is σ = 65408643840. Its totient is φ = 43458384384.
The previous prime is 54415051333. The next prime is 54415051447.
54415051445 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 54415051445 - 222 = 54410857141 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 54415051399 and 54415051408.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54415051447) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11912552 + ... + 11917118.
It is an arithmetic number, because the mean of its divisors is an integer number (4088040240).
Almost surely, 254415051445 is an apocalyptic number.
It is an amenable number.
54415051445 is a deficient number, since it is larger than the sum of its proper divisors (10993592395).
54415051445 is a wasteful number, since it uses less digits than its factorization.
54415051445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8084.
The product of its (nonzero) digits is 160000, while the sum is 38.
It can be divided in two parts, 544150 and 51445, that added together give a palindrome (595595).
The spelling of 54415051445 in words is "fifty-four billion, four hundred fifteen million, fifty-one thousand, four hundred forty-five".
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