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544302054044 = 22719439359073
BaseRepresentation
bin1111110101110101110…
…11100011101010011100
31221000221100100020102222
413322322323203222130
532404212311212134
61054014322004512
754216212056640
oct7727273435234
91830840306388
10544302054044
1119a923357401
12895a57a6738
133c43458b738
141c4b6cd0c20
15e25a157a2e
hex7ebaee3a9c

544302054044 has 12 divisors (see below), whose sum is σ = 1088604108144. Its totient is φ = 233272308864.

The previous prime is 544302054019. The next prime is 544302054053. The reversal of 544302054044 is 440450203445.

544302054044 is an admirable number.

It is a junction number, because it is equal to n+sod(n) for n = 544302053995 and 544302054013.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9719679509 + ... + 9719679564.

It is an arithmetic number, because the mean of its divisors is an integer number (90717009012).

Almost surely, 2544302054044 is an apocalyptic number.

It is an amenable number.

544302054044 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

544302054044 is a wasteful number, since it uses less digits than its factorization.

544302054044 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19439359084 (or 19439359082 counting only the distinct ones).

The product of its (nonzero) digits is 153600, while the sum is 35.

Adding to 544302054044 its reverse (440450203445), we get a palindrome (984752257489).

The spelling of 544302054044 in words is "five hundred forty-four billion, three hundred two million, fifty-four thousand, forty-four".

Divisors: 1 2 4 7 14 28 19439359073 38878718146 77757436292 136075513511 272151027022 544302054044