Base | Representation |
---|---|
bin | 110010101100100110… |
… | …101110010100101001 |
3 | 12012111200212212100012 |
4 | 302230212232110221 |
5 | 1342440433034123 |
6 | 41001324221305 |
7 | 3634650414311 |
oct | 625446562451 |
9 | 165450785305 |
10 | 54435439913 |
11 | 210a4428778 |
12 | a67239a835 |
13 | 5196960a9a |
14 | 28c5832441 |
15 | 1638e7e378 |
hex | cac9ae529 |
54435439913 has 2 divisors, whose sum is σ = 54435439914. Its totient is φ = 54435439912.
The previous prime is 54435439901. The next prime is 54435439939. The reversal of 54435439913 is 31993453445.
54435439913 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 38356439104 + 16079000809 = 195848^2 + 126803^2 .
It is a cyclic number.
It is not a de Polignac number, because 54435439913 - 228 = 54167004457 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (54435439943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27217719956 + 27217719957.
It is an arithmetic number, because the mean of its divisors is an integer number (27217719957).
Almost surely, 254435439913 is an apocalyptic number.
It is an amenable number.
54435439913 is a deficient number, since it is larger than the sum of its proper divisors (1).
54435439913 is an equidigital number, since it uses as much as digits as its factorization.
54435439913 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3499200, while the sum is 50.
The spelling of 54435439913 in words is "fifty-four billion, four hundred thirty-five million, four hundred thirty-nine thousand, nine hundred thirteen".
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