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54440524341304 = 2322133307462411
BaseRepresentation
bin11000110000011011011000…
…00111010110000000111000
321010202110111202010011121121
430120031230013112000320
524113423143212410204
6311441344232515024
714316124641513013
oct1430155407260070
9233673452104547
1054440524341304
111638a107802512
126132b3154ba74
13244b94773780a
14d62d14ba837a
156461ca070b54
hex31836c1d6038

54440524341304 has 16 divisors (see below), whose sum is σ = 102080595408120. Its totient is φ = 27219032232480.

The previous prime is 54440524341271. The next prime is 54440524341373. The reversal of 54440524341304 is 40314342504445.

It is a super-3 number, since 3×544405243413043 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 153554142 + ... + 153908269.

Almost surely, 254440524341304 is an apocalyptic number.

It is an amenable number.

54440524341304 is a deficient number, since it is larger than the sum of its proper divisors (47640071066816).

54440524341304 is a wasteful number, since it uses less digits than its factorization.

54440524341304 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 307484550 (or 307484546 counting only the distinct ones).

The product of its (nonzero) digits is 1843200, while the sum is 43.

Adding to 54440524341304 its reverse (40314342504445), we get a palindrome (94754866845749).

The spelling of 54440524341304 in words is "fifty-four trillion, four hundred forty billion, five hundred twenty-four million, three hundred forty-one thousand, three hundred four".

Divisors: 1 2 4 8 22133 44266 88532 177064 307462411 614924822 1229849644 2459699288 6805065542663 13610131085326 27220262170652 54440524341304