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544813640131 is a prime number
BaseRepresentation
bin1111110110110010110…
…11000110100111000011
31221002020222222111121211
413323121123012213003
532411234242441011
61054141155030551
754234663350365
oct7733133064703
91832228874554
10544813640131
111a0066107622
1289708b9b457
133c4b656c2b7
141c524c20d35
15e28a00db21
hex7ed96c69c3

544813640131 has 2 divisors, whose sum is σ = 544813640132. Its totient is φ = 544813640130.

The previous prime is 544813640123. The next prime is 544813640183. The reversal of 544813640131 is 131046318445.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 544813640131 - 23 = 544813640123 is a prime.

It is a super-2 number, since 2×5448136401312 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (544813640191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272406820065 + 272406820066.

It is an arithmetic number, because the mean of its divisors is an integer number (272406820066).

Almost surely, 2544813640131 is an apocalyptic number.

544813640131 is a deficient number, since it is larger than the sum of its proper divisors (1).

544813640131 is an equidigital number, since it uses as much as digits as its factorization.

544813640131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 138240, while the sum is 40.

Adding to 544813640131 its reverse (131046318445), we get a palindrome (675859958576).

The spelling of 544813640131 in words is "five hundred forty-four billion, eight hundred thirteen million, six hundred forty thousand, one hundred thirty-one".