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545021306131 is a prime number
BaseRepresentation
bin1111110111001011100…
…11010010010100010011
31221002210110202000211011
413323211303102110103
532412200423244011
61054213534031351
754243064443541
oct7734563222423
91832713660734
10545021306131
111a0162356115
1289766648557
133c51a5ab9a3
141c54463ad91
15e29d37e621
hex7ee5cd2513

545021306131 has 2 divisors, whose sum is σ = 545021306132. Its totient is φ = 545021306130.

The previous prime is 545021306083. The next prime is 545021306143. The reversal of 545021306131 is 131603120545.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 545021306131 - 217 = 545021175059 is a prime.

It is a super-3 number, since 3×5450213061313 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 545021306093 and 545021306102.

It is not a weakly prime, because it can be changed into another prime (545021306191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272510653065 + 272510653066.

It is an arithmetic number, because the mean of its divisors is an integer number (272510653066).

Almost surely, 2545021306131 is an apocalyptic number.

545021306131 is a deficient number, since it is larger than the sum of its proper divisors (1).

545021306131 is an equidigital number, since it uses as much as digits as its factorization.

545021306131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 545021306131 its reverse (131603120545), we get a palindrome (676624426676).

The spelling of 545021306131 in words is "five hundred forty-five billion, twenty-one million, three hundred six thousand, one hundred thirty-one".