Base | Representation |
---|---|
bin | 11000110010011111110010… |
… | …10110101111000110011011 |
3 | 21011000021000001210120121011 |
4 | 30121033321112233012123 |
5 | 24121104241020043121 |
6 | 311534142310554351 |
7 | 14324222412054511 |
oct | 1431177126570633 |
9 | 234007001716534 |
10 | 54511613440411 |
11 | 16407277743896 |
12 | 61448710689b7 |
13 | 24555666b71ba |
14 | d6653a2c24b1 |
15 | 647e8b0b27e1 |
hex | 3193f95af19b |
54511613440411 has 2 divisors, whose sum is σ = 54511613440412. Its totient is φ = 54511613440410.
The previous prime is 54511613440397. The next prime is 54511613440499. The reversal of 54511613440411 is 11404431611545.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54511613440411 - 217 = 54511613309339 is a prime.
It is not a weakly prime, because it can be changed into another prime (54511613440811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27255806720205 + 27255806720206.
It is an arithmetic number, because the mean of its divisors is an integer number (27255806720206).
Almost surely, 254511613440411 is an apocalyptic number.
54511613440411 is a deficient number, since it is larger than the sum of its proper divisors (1).
54511613440411 is an equidigital number, since it uses as much as digits as its factorization.
54511613440411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 115200, while the sum is 40.
The spelling of 54511613440411 in words is "fifty-four trillion, five hundred eleven billion, six hundred thirteen million, four hundred forty thousand, four hundred eleven".
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