Base | Representation |
---|---|
bin | 100111101100011000010… |
… | …0011011001110101001011 |
3 | 201022112101210221022101112 |
4 | 1033120300203121311023 |
5 | 1203340201300200011 |
6 | 15334104201040535 |
7 | 1102066316561342 |
oct | 117306043316513 |
9 | 21275353838345 |
10 | 5455423053131 |
11 | 18136a50aaaa7 |
12 | 74136a18614b |
13 | 3075a0b544ac |
14 | 14c0885c2b59 |
15 | 96d94b3058b |
hex | 4f6308d9d4b |
5455423053131 has 2 divisors, whose sum is σ = 5455423053132. Its totient is φ = 5455423053130.
The previous prime is 5455423053121. The next prime is 5455423053167. The reversal of 5455423053131 is 1313503245545.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5455423053131 is a prime.
It is a super-2 number, since 2×54554230531312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5455423053121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2727711526565 + 2727711526566.
It is an arithmetic number, because the mean of its divisors is an integer number (2727711526566).
Almost surely, 25455423053131 is an apocalyptic number.
5455423053131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5455423053131 is an equidigital number, since it uses as much as digits as its factorization.
5455423053131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540000, while the sum is 41.
Adding to 5455423053131 its reverse (1313503245545), we get a palindrome (6768926298676).
The spelling of 5455423053131 in words is "five trillion, four hundred fifty-five billion, four hundred twenty-three million, fifty-three thousand, one hundred thirty-one".
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