Base | Representation |
---|---|
bin | 1111111001000000010… |
… | …10010010010110110011 |
3 | 1221012022201002212111102 |
4 | 13330200022102112303 |
5 | 32421202101223011 |
6 | 1054455031435015 |
7 | 54306253642034 |
oct | 7744012222663 |
9 | 1835281085442 |
10 | 546000414131 |
11 | 1a0614aaa487 |
12 | 8999a525a6b |
13 | 3c6453b2733 |
14 | 1c5d86aaa8b |
15 | e3092d573b |
hex | 7f202925b3 |
546000414131 has 2 divisors, whose sum is σ = 546000414132. Its totient is φ = 546000414130.
The previous prime is 546000414103. The next prime is 546000414221. The reversal of 546000414131 is 131414000645.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 546000414131 - 210 = 546000413107 is a prime.
It is a super-2 number, since 2×5460004141312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 546000414094 and 546000414103.
It is not a weakly prime, because it can be changed into another prime (546000414031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 273000207065 + 273000207066.
It is an arithmetic number, because the mean of its divisors is an integer number (273000207066).
Almost surely, 2546000414131 is an apocalyptic number.
546000414131 is a deficient number, since it is larger than the sum of its proper divisors (1).
546000414131 is an equidigital number, since it uses as much as digits as its factorization.
546000414131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 546000414131 its reverse (131414000645), we get a palindrome (677414414776).
The spelling of 546000414131 in words is "five hundred forty-six billion, four hundred fourteen thousand, one hundred thirty-one".
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