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54610665433 is a prime number
BaseRepresentation
bin110010110111000011…
…001001111111011001
312012221220121020120021
4302313003021333121
51343320312243213
641030544030441
73642205666012
oct626703117731
9165856536507
1054610665433
112118432a255
12a701002421
1351c405271c
142900c06009
151649542d8d
hexcb70c9fd9

54610665433 has 2 divisors, whose sum is σ = 54610665434. Its totient is φ = 54610665432.

The previous prime is 54610665427. The next prime is 54610665437. The reversal of 54610665433 is 33456601645.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36089360784 + 18521304649 = 189972^2 + 136093^2 .

It is a cyclic number.

It is not a de Polignac number, because 54610665433 - 29 = 54610664921 is a prime.

It is a super-2 number, since 2×546106654332 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 54610665433.

It is not a weakly prime, because it can be changed into another prime (54610665437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27305332716 + 27305332717.

It is an arithmetic number, because the mean of its divisors is an integer number (27305332717).

Almost surely, 254610665433 is an apocalyptic number.

It is an amenable number.

54610665433 is a deficient number, since it is larger than the sum of its proper divisors (1).

54610665433 is an equidigital number, since it uses as much as digits as its factorization.

54610665433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 777600, while the sum is 43.

The spelling of 54610665433 in words is "fifty-four billion, six hundred ten million, six hundred sixty-five thousand, four hundred thirty-three".