Base | Representation |
---|---|
bin | 11000110101011001010111… |
… | …10000001011111000001011 |
3 | 21011100210011102210210120222 |
4 | 30122230223300023320023 |
5 | 24124222311231023431 |
6 | 312052020410540255 |
7 | 14334350342162606 |
oct | 1432545360137013 |
9 | 234323142723528 |
10 | 54611243220491 |
11 | 164455530a4211 |
12 | 6160036a3768b |
13 | 2461a835b11a9 |
14 | d6b2ac0d133d |
15 | 64a86ca6c57b |
hex | 31ab2bc0be0b |
54611243220491 has 2 divisors, whose sum is σ = 54611243220492. Its totient is φ = 54611243220490.
The previous prime is 54611243220461. The next prime is 54611243220497. The reversal of 54611243220491 is 19402234211645.
54611243220491 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54611243220491 - 218 = 54611242958347 is a prime.
It is not a weakly prime, because it can be changed into another prime (54611243220497) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27305621610245 + 27305621610246.
It is an arithmetic number, because the mean of its divisors is an integer number (27305621610246).
Almost surely, 254611243220491 is an apocalyptic number.
54611243220491 is a deficient number, since it is larger than the sum of its proper divisors (1).
54611243220491 is an equidigital number, since it uses as much as digits as its factorization.
54611243220491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 414720, while the sum is 44.
The spelling of 54611243220491 in words is "fifty-four trillion, six hundred eleven billion, two hundred forty-three million, two hundred twenty thousand, four hundred ninety-one".
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