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54611523343313 is a prime number
BaseRepresentation
bin11000110101011001111000…
…11100110001001111010001
321011100210212221220111212022
430122230330130301033101
524124223344433441223
6312052104254541225
714334360313164326
oct1432547434611721
9234323787814768
1054611523343313
1116445687231682
1261600b4807815
132461ac963c741
14d6b2d73acb4d
1564a887451ac8
hex31ab3c7313d1

54611523343313 has 2 divisors, whose sum is σ = 54611523343314. Its totient is φ = 54611523343312.

The previous prime is 54611523343277. The next prime is 54611523343337. The reversal of 54611523343313 is 31334332511645.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 35560803770944 + 19050719572369 = 5963288^2 + 4364713^2 .

It is a cyclic number.

It is not a de Polignac number, because 54611523343313 - 216 = 54611523277777 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (54611523343613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27305761671656 + 27305761671657.

It is an arithmetic number, because the mean of its divisors is an integer number (27305761671657).

Almost surely, 254611523343313 is an apocalyptic number.

It is an amenable number.

54611523343313 is a deficient number, since it is larger than the sum of its proper divisors (1).

54611523343313 is an equidigital number, since it uses as much as digits as its factorization.

54611523343313 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1166400, while the sum is 44.

Adding to 54611523343313 its reverse (31334332511645), we get a palindrome (85945855854958).

The spelling of 54611523343313 in words is "fifty-four trillion, six hundred eleven billion, five hundred twenty-three million, three hundred forty-three thousand, three hundred thirteen".