Base | Representation |
---|---|
bin | 11000110111010110011111… |
… | …11100110000001001101011 |
3 | 21011121012120021110011110012 |
4 | 30123223033330300021223 |
5 | 24131322402124101114 |
6 | 312142530455442135 |
7 | 14342246165423435 |
oct | 1433531774601153 |
9 | 234535507404405 |
10 | 54678422487659 |
11 | 16470a97037a23 |
12 | 617106508634b |
13 | 24681cb51c759 |
14 | d70642247655 |
15 | 64c4a06ea63e |
hex | 31bacff3026b |
54678422487659 has 2 divisors, whose sum is σ = 54678422487660. Its totient is φ = 54678422487658.
The previous prime is 54678422487553. The next prime is 54678422487691. The reversal of 54678422487659 is 95678422487645.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54678422487659 - 224 = 54678405710443 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 54678422487659.
It is not a weakly prime, because it can be changed into another prime (54678422487259) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27339211243829 + 27339211243830.
It is an arithmetic number, because the mean of its divisors is an integer number (27339211243830).
Almost surely, 254678422487659 is an apocalyptic number.
54678422487659 is a deficient number, since it is larger than the sum of its proper divisors (1).
54678422487659 is an equidigital number, since it uses as much as digits as its factorization.
54678422487659 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6502809600, while the sum is 77.
The spelling of 54678422487659 in words is "fifty-four trillion, six hundred seventy-eight billion, four hundred twenty-two million, four hundred eighty-seven thousand, six hundred fifty-nine".
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