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5470311477101 = 26017121025831
BaseRepresentation
bin100111110011010011111…
…1110001110111101101101
3201100221211102010121112112
41033212213332032331231
51204111144214231401
615345005411413405
71103134263233252
oct117464776167555
921327742117475
105470311477101
111819a45244319
127442242b4265
13308b04535a13
1414ca9ba81429
1597466c553bb
hex4f9a7f8ef6d

5470311477101 has 4 divisors (see below), whose sum is σ = 5470332763104. Its totient is φ = 5470290191100.

The previous prime is 5470311477079. The next prime is 5470311477157. The reversal of 5470311477101 is 1017741130745.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5470311477101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5470311477161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10252745 + ... + 10773086.

It is an arithmetic number, because the mean of its divisors is an integer number (1367583190776).

Almost surely, 25470311477101 is an apocalyptic number.

It is an amenable number.

5470311477101 is a deficient number, since it is larger than the sum of its proper divisors (21286003).

5470311477101 is a wasteful number, since it uses less digits than its factorization.

5470311477101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21286002.

The product of its (nonzero) digits is 82320, while the sum is 41.

The spelling of 5470311477101 in words is "five trillion, four hundred seventy billion, three hundred eleven million, four hundred seventy-seven thousand, one hundred one".

Divisors: 1 260171 21025831 5470311477101