Base | Representation |
---|---|
bin | 100111110011010011111… |
… | …1110001110111110100101 |
3 | 201100221211102010121121121 |
4 | 1033212213332032332211 |
5 | 1204111144214232112 |
6 | 15345005411413541 |
7 | 1103134263233362 |
oct | 117464776167645 |
9 | 21327742117547 |
10 | 5470311477157 |
11 | 1819a4524436a |
12 | 7442242b42b1 |
13 | 308b04535a57 |
14 | 14ca9ba81469 |
15 | 97466c55407 |
hex | 4f9a7f8efa5 |
5470311477157 has 2 divisors, whose sum is σ = 5470311477158. Its totient is φ = 5470311477156.
The previous prime is 5470311477079. The next prime is 5470311477161. The reversal of 5470311477157 is 7517741130745.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4743122092641 + 727189384516 = 2177871^2 + 852754^2 .
It is a cyclic number.
It is not a de Polignac number, because 5470311477157 - 239 = 4920555663269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5470311477457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2735155738578 + 2735155738579.
It is an arithmetic number, because the mean of its divisors is an integer number (2735155738579).
Almost surely, 25470311477157 is an apocalyptic number.
It is an amenable number.
5470311477157 is a deficient number, since it is larger than the sum of its proper divisors (1).
5470311477157 is an equidigital number, since it uses as much as digits as its factorization.
5470311477157 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2881200, while the sum is 52.
The spelling of 5470311477157 in words is "five trillion, four hundred seventy billion, three hundred eleven million, four hundred seventy-seven thousand, one hundred fifty-seven".
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