Base | Representation |
---|---|
bin | 110010111100101100… |
… | …111111101011100011 |
3 | 12020012112002022122121 |
4 | 302330230333223203 |
5 | 1344014103104311 |
6 | 41044213045111 |
7 | 3644440146001 |
oct | 627454775343 |
9 | 166175068577 |
10 | 54705519331 |
11 | 21222926401 |
12 | a728926797 |
13 | 520a8b3aa8 |
14 | 290d657a71 |
15 | 1652a2cb71 |
hex | cbcb3fae3 |
54705519331 has 2 divisors, whose sum is σ = 54705519332. Its totient is φ = 54705519330.
The previous prime is 54705519317. The next prime is 54705519353. The reversal of 54705519331 is 13391550745.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54705519331 - 213 = 54705511139 is a prime.
It is a super-2 number, since 2×547055193312 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (54705519361) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27352759665 + 27352759666.
It is an arithmetic number, because the mean of its divisors is an integer number (27352759666).
Almost surely, 254705519331 is an apocalyptic number.
54705519331 is a deficient number, since it is larger than the sum of its proper divisors (1).
54705519331 is an equidigital number, since it uses as much as digits as its factorization.
54705519331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 283500, while the sum is 43.
The spelling of 54705519331 in words is "fifty-four billion, seven hundred five million, five hundred nineteen thousand, three hundred thirty-one".
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