Base | Representation |
---|---|
bin | 110010111101000111… |
… | …010101001011110001 |
3 | 12020020000002001220201 |
4 | 302331013111023301 |
5 | 1344022340020103 |
6 | 41045021035201 |
7 | 3644552631523 |
oct | 627507251361 |
9 | 166200061821 |
10 | 54712423153 |
11 | 21226811343 |
12 | a72b0b5b01 |
13 | 520c1602ab |
14 | 2910533a13 |
15 | 165344351d |
hex | cbd1d52f1 |
54712423153 has 2 divisors, whose sum is σ = 54712423154. Its totient is φ = 54712423152.
The previous prime is 54712423133. The next prime is 54712423159. The reversal of 54712423153 is 35132421745.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 53699719824 + 1012703329 = 231732^2 + 31823^2 .
It is a cyclic number.
It is not a de Polignac number, because 54712423153 - 225 = 54678868721 is a prime.
It is a super-2 number, since 2×547124231532 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (54712423159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27356211576 + 27356211577.
It is an arithmetic number, because the mean of its divisors is an integer number (27356211577).
Almost surely, 254712423153 is an apocalyptic number.
It is an amenable number.
54712423153 is a deficient number, since it is larger than the sum of its proper divisors (1).
54712423153 is an equidigital number, since it uses as much as digits as its factorization.
54712423153 is an evil number, because the sum of its binary digits is even.
The product of its digits is 100800, while the sum is 37.
Adding to 54712423153 its reverse (35132421745), we get a palindrome (89844844898).
The spelling of 54712423153 in words is "fifty-four billion, seven hundred twelve million, four hundred twenty-three thousand, one hundred fifty-three".
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