Base | Representation |
---|---|
bin | 1010001100001111… |
… | …00101100110101011 |
3 | 112010022022221220201 |
4 | 11012013211212223 |
5 | 42201132031301 |
6 | 2302530133031 |
7 | 252404543053 |
oct | 50607454653 |
9 | 15108287821 |
10 | 5471361451 |
11 | 2358493926 |
12 | 1088421177 |
13 | 6926c75aa |
14 | 39c920563 |
15 | 220514201 |
hex | 1461e59ab |
5471361451 has 2 divisors, whose sum is σ = 5471361452. Its totient is φ = 5471361450.
The previous prime is 5471361403. The next prime is 5471361479. The reversal of 5471361451 is 1541631745.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5471361451 is a prime.
It is a super-2 number, since 2×54713614512 = 59871592254977650802, which contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5471361451.
It is not a weakly prime, because it can be changed into another prime (5471361551) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2735680725 + 2735680726.
It is an arithmetic number, because the mean of its divisors is an integer number (2735680726).
Almost surely, 25471361451 is an apocalyptic number.
5471361451 is a deficient number, since it is larger than the sum of its proper divisors (1).
5471361451 is an equidigital number, since it uses as much as digits as its factorization.
5471361451 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 50400, while the sum is 37.
The square root of 5471361451 is about 73968.6518127781. The cubic root of 5471361451 is about 1762.1050753470.
The spelling of 5471361451 in words is "five billion, four hundred seventy-one million, three hundred sixty-one thousand, four hundred fifty-one".
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