Base | Representation |
---|---|
bin | 11000111000110111100011… |
… | …00001110000001110111000 |
3 | 21011210012001102100112110220 |
4 | 30130123301201300032320 |
5 | 24133201104003134000 |
6 | 312222504542540040 |
7 | 14346102304302351 |
oct | 1434336141601670 |
9 | 234705042315426 |
10 | 54730525443000 |
11 | 164910a38774a0 |
12 | 617b186297620 |
13 | 24700b2b73544 |
14 | d72d85d92d28 |
15 | 64d9ee9dd1a0 |
hex | 31c6f18703b8 |
54730525443000 has 256 divisors, whose sum is σ = 188527187197440. Its totient is φ = 13108150016000.
The previous prime is 54730525442959. The next prime is 54730525443037. The reversal of 54730525443000 is 34452503745.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7251969 + ... + 12729968.
It is an arithmetic number, because the mean of its divisors is an integer number (736434324990).
Almost surely, 254730525443000 is an apocalyptic number.
54730525443000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
54730525443000 is an abundant number, since it is smaller than the sum of its proper divisors (133796661754440).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
54730525443000 is a wasteful number, since it uses less digits than its factorization.
54730525443000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19982055 (or 19982041 counting only the distinct ones).
The product of its (nonzero) digits is 1008000, while the sum is 42.
Adding to 54730525443000 its reverse (34452503745), we get a palindrome (54764977946745).
The spelling of 54730525443000 in words is "fifty-four trillion, seven hundred thirty billion, five hundred twenty-five million, four hundred forty-three thousand".
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