Base | Representation |
---|---|
bin | 11000111001001111101001… |
… | …10111101110000010111001 |
3 | 21011211102110022010000211110 |
4 | 30130213310313232002321 |
5 | 24133404104401402440 |
6 | 312232445025150533 |
7 | 14350041063023304 |
oct | 1434476467560271 |
9 | 234742408100743 |
10 | 54743466434745 |
11 | 164966347090a0 |
12 | 618179818b449 |
13 | 2471395c547ca |
14 | d7385295bb3b |
15 | 64e00ab86080 |
hex | 31c9f4dee0b9 |
54743466434745 has 64 divisors (see below), whose sum is σ = 98141871815424. Its totient is φ = 25823046942720.
The previous prime is 54743466434737. The next prime is 54743466434791.
54743466434745 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 54743466434745 - 23 = 54743466434737 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 85351969 + ... + 85990961.
It is an arithmetic number, because the mean of its divisors is an integer number (1533466747116).
Almost surely, 254743466434745 is an apocalyptic number.
54743466434745 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
54743466434745 is a deficient number, since it is larger than the sum of its proper divisors (43398405380679).
54743466434745 is a wasteful number, since it uses less digits than its factorization.
54743466434745 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 653082.
The product of its digits is 1625702400, while the sum is 66.
The spelling of 54743466434745 in words is "fifty-four trillion, seven hundred forty-three billion, four hundred sixty-six million, four hundred thirty-four thousand, seven hundred forty-five".
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