Base | Representation |
---|---|
bin | 11000111011111110000110… |
… | …10111010111011111101011 |
3 | 21012011101012112111202201002 |
4 | 30131333003113113133223 |
5 | 24141422413014310244 |
6 | 312343454424345215 |
7 | 14356565040000233 |
oct | 1435770327273753 |
9 | 235141175452632 |
10 | 54837125150699 |
11 | 16522326601681 |
12 | 619797631520b |
13 | 247a170a74568 |
14 | d781b9730cc3 |
15 | 65168d321a4e |
hex | 31dfc35d77eb |
54837125150699 has 2 divisors, whose sum is σ = 54837125150700. Its totient is φ = 54837125150698.
The previous prime is 54837125150627. The next prime is 54837125150711. The reversal of 54837125150699 is 99605152173845.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54837125150699 - 228 = 54836856715243 is a prime.
It is a super-2 number, since 2×548371251506992 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (54837125150399) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27418562575349 + 27418562575350.
It is an arithmetic number, because the mean of its divisors is an integer number (27418562575350).
It is a 2-persistent number, because it is pandigital, and so is 2⋅54837125150699 = 109674250301398, but 3⋅54837125150699 = 164511375452097 is not.
Almost surely, 254837125150699 is an apocalyptic number.
54837125150699 is a deficient number, since it is larger than the sum of its proper divisors (1).
54837125150699 is an equidigital number, since it uses as much as digits as its factorization.
54837125150699 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81648000, while the sum is 65.
The spelling of 54837125150699 in words is "fifty-four trillion, eight hundred thirty-seven billion, one hundred twenty-five million, one hundred fifty thousand, six hundred ninety-nine".
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