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5483778981377 is a prime number
BaseRepresentation
bin100111111001100101010…
…1100101011111000000001
3201102020120222121201022012
41033303022230223320001
51204321234404401002
615355114023022305
71104122104153154
oct117631254537001
921366528551265
105483778981377
111824726300644
1274696259a995
1330a16c722868
1414d5b8543c9b
15979a4251d52
hex4fccab2be01

5483778981377 has 2 divisors, whose sum is σ = 5483778981378. Its totient is φ = 5483778981376.

The previous prime is 5483778981313. The next prime is 5483778981389. The reversal of 5483778981377 is 7731898773845.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4277715973696 + 1206063007681 = 2068264^2 + 1098209^2 .

It is a cyclic number.

It is not a de Polignac number, because 5483778981377 - 26 = 5483778981313 is a prime.

It is a super-2 number, since 2×54837789813772 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5483778981298 and 5483778981307.

It is not a weakly prime, because it can be changed into another prime (5483778981677) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2741889490688 + 2741889490689.

It is an arithmetic number, because the mean of its divisors is an integer number (2741889490689).

Almost surely, 25483778981377 is an apocalyptic number.

It is an amenable number.

5483778981377 is a deficient number, since it is larger than the sum of its proper divisors (1).

5483778981377 is an equidigital number, since it uses as much as digits as its factorization.

5483778981377 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1991485440, while the sum is 77.

The spelling of 5483778981377 in words is "five trillion, four hundred eighty-three billion, seven hundred seventy-eight million, nine hundred eighty-one thousand, three hundred seventy-seven".