Base | Representation |
---|---|
bin | 11000111100101101011110… |
… | …01111101101111000010001 |
3 | 21012020210211221210010112001 |
4 | 30132112233033231320101 |
5 | 24142332004143422224 |
6 | 312403302210034001 |
7 | 14361455213410306 |
oct | 1436265717557021 |
9 | 235223757703461 |
10 | 54862557404689 |
11 | 16532097433501 |
12 | 61a0893578901 |
13 | 247c694a03268 |
14 | d7950d2770ad |
15 | 65217ae29544 |
hex | 31e5af3ede11 |
54862557404689 has 2 divisors, whose sum is σ = 54862557404690. Its totient is φ = 54862557404688.
The previous prime is 54862557404539. The next prime is 54862557404803. The reversal of 54862557404689 is 98640475526845.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 34850426730625 + 20012130674064 = 5903425^2 + 4473492^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54862557404689 is a prime.
It is not a weakly prime, because it can be changed into another prime (54862657404689) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27431278702344 + 27431278702345.
It is an arithmetic number, because the mean of its divisors is an integer number (27431278702345).
Almost surely, 254862557404689 is an apocalyptic number.
It is an amenable number.
54862557404689 is a deficient number, since it is larger than the sum of its proper divisors (1).
54862557404689 is an equidigital number, since it uses as much as digits as its factorization.
54862557404689 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2322432000, while the sum is 73.
The spelling of 54862557404689 in words is "fifty-four trillion, eight hundred sixty-two billion, five hundred fifty-seven million, four hundred four thousand, six hundred eighty-nine".
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