Base | Representation |
---|---|
bin | 100111111101000111100… |
… | …0100000011110000010011 |
3 | 201102222011220110122100001 |
4 | 1033322033010003300103 |
5 | 1204432310303111011 |
6 | 15402411054510431 |
7 | 1104511141222462 |
oct | 117721704036023 |
9 | 21388156418301 |
10 | 5491368410131 |
11 | 182797034280a |
12 | 748320205417 |
13 | 30aaabb927c6 |
14 | 14dad84949d9 |
15 | 97c9a69b7c1 |
hex | 4fe8f103c13 |
5491368410131 has 2 divisors, whose sum is σ = 5491368410132. Its totient is φ = 5491368410130.
The previous prime is 5491368410093. The next prime is 5491368410137. The reversal of 5491368410131 is 1310148631945.
5491368410131 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5491368410131 - 221 = 5491366312979 is a prime.
It is a super-2 number, since 2×54913684101312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5491368410137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2745684205065 + 2745684205066.
It is an arithmetic number, because the mean of its divisors is an integer number (2745684205066).
Almost surely, 25491368410131 is an apocalyptic number.
5491368410131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5491368410131 is an equidigital number, since it uses as much as digits as its factorization.
5491368410131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 311040, while the sum is 46.
The spelling of 5491368410131 in words is "five trillion, four hundred ninety-one billion, three hundred sixty-eight million, four hundred ten thousand, one hundred thirty-one".
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