Base | Representation |
---|---|
bin | 11000111110111000010001… |
… | …11101101100100000011001 |
3 | 21012111221012100200120001021 |
4 | 30133130020331230200121 |
5 | 24200042113212331240 |
6 | 312501424513122441 |
7 | 14400033661221253 |
oct | 1437341075544031 |
9 | 235457170616037 |
10 | 54937077073945 |
11 | 1656075788aa20 |
12 | 61b320bb59421 |
13 | 248670c620101 |
14 | d7cd7c238cd3 |
15 | 65408d21154a |
hex | 31f708f6c819 |
54937077073945 has 32 divisors (see below), whose sum is σ = 75703712071680. Its totient is φ = 37850910459840.
The previous prime is 54937077073909. The next prime is 54937077073973.
54937077073945 is nontrivially palindromic in base 10.
54937077073945 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 54937077073945 - 211 = 54937077071897 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 97240872 + ... + 97804198.
It is an arithmetic number, because the mean of its divisors is an integer number (2365741002240).
Almost surely, 254937077073945 is an apocalyptic number.
54937077073945 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
54937077073945 is a deficient number, since it is larger than the sum of its proper divisors (20766634997735).
54937077073945 is a wasteful number, since it uses less digits than its factorization.
54937077073945 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 656685.
The product of its (nonzero) digits is 700131600, while the sum is 70.
The spelling of 54937077073945 in words is "fifty-four trillion, nine hundred thirty-seven billion, seventy-seven million, seventy-three thousand, nine hundred forty-five".
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