Base | Representation |
---|---|
bin | 110011001100000001… |
… | …010001100111011001 |
3 | 12020212102121222111201 |
4 | 303030001101213121 |
5 | 1400030344301123 |
6 | 41125512554201 |
7 | 3654010330015 |
oct | 631401214731 |
9 | 166772558451 |
10 | 54962493913 |
11 | 21344993198 |
12 | a79a9b2961 |
13 | 524bbc8c62 |
14 | 293582b545 |
15 | 166a38d5ad |
hex | ccc0519d9 |
54962493913 has 2 divisors, whose sum is σ = 54962493914. Its totient is φ = 54962493912.
The previous prime is 54962493877. The next prime is 54962493917. The reversal of 54962493913 is 31939426945.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 43732429129 + 11230064784 = 209123^2 + 105972^2 .
It is a cyclic number.
It is not a de Polignac number, because 54962493913 - 29 = 54962493401 is a prime.
It is not a weakly prime, because it can be changed into another prime (54962493917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27481246956 + 27481246957.
It is an arithmetic number, because the mean of its divisors is an integer number (27481246957).
Almost surely, 254962493913 is an apocalyptic number.
It is an amenable number.
54962493913 is a deficient number, since it is larger than the sum of its proper divisors (1).
54962493913 is an equidigital number, since it uses as much as digits as its factorization.
54962493913 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6298560, while the sum is 55.
The spelling of 54962493913 in words is "fifty-four billion, nine hundred sixty-two million, four hundred ninety-three thousand, nine hundred thirteen".
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