Base | Representation |
---|---|
bin | 101000000001001000110… |
… | …0011001001011101111001 |
3 | 201110210110110102022220011 |
4 | 1100002101203021131321 |
5 | 1210103000003032032 |
6 | 15410355400501521 |
7 | 1105235062024435 |
oct | 120022143113571 |
9 | 21423413368804 |
10 | 5500000049017 |
11 | 183059a708871 |
12 | 749b2aa7a8a1 |
13 | 30b85622b436 |
14 | 1502b69bd9c5 |
15 | 98103364247 |
hex | 500918c9779 |
5500000049017 has 2 divisors, whose sum is σ = 5500000049018. Its totient is φ = 5500000049016.
The previous prime is 5500000049009. The next prime is 5500000049023. The reversal of 5500000049017 is 7109400000055.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5340993701481 + 159006347536 = 2311059^2 + 398756^2 .
It is a cyclic number.
It is not a de Polignac number, because 5500000049017 - 23 = 5500000049009 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5500000049017.
It is not a weakly prime, because it can be changed into another prime (5500000049617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2750000024508 + 2750000024509.
It is an arithmetic number, because the mean of its divisors is an integer number (2750000024509).
Almost surely, 25500000049017 is an apocalyptic number.
It is an amenable number.
5500000049017 is a deficient number, since it is larger than the sum of its proper divisors (1).
5500000049017 is an equidigital number, since it uses as much as digits as its factorization.
5500000049017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6300, while the sum is 31.
The spelling of 5500000049017 in words is "five trillion, five hundred billion, forty-nine thousand, seventeen".
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