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55000403 is a prime number
BaseRepresentation
bin1101000111001…
…1110101010011
310211111022100222
43101303311103
5103040003103
65242503255
71235332013
oct321636523
9124438328
1055000403
1129056687
1216504b2b
13b519423
147439c43
154c66638
hex3473d53

55000403 has 2 divisors, whose sum is σ = 55000404. Its totient is φ = 55000402.

The previous prime is 55000369. The next prime is 55000469. The reversal of 55000403 is 30400055.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 55000403 - 210 = 54999379 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (55002403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27500201 + 27500202.

It is an arithmetic number, because the mean of its divisors is an integer number (27500202).

Almost surely, 255000403 is an apocalyptic number.

55000403 is a deficient number, since it is larger than the sum of its proper divisors (1).

55000403 is an equidigital number, since it uses as much as digits as its factorization.

55000403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 300, while the sum is 17.

The square root of 55000403 is about 7416.2256573003. The cubic root of 55000403 is about 380.2961749162.

Adding to 55000403 its reverse (30400055), we get a palindrome (85400458).

The spelling of 55000403 in words is "fifty-five million, four hundred three", and thus it is an aban number.