Base | Representation |
---|---|
bin | 11001000000101110100111… |
… | …11000011010010010100001 |
3 | 21012202000012010222200200010 |
4 | 30200113103320122102201 |
5 | 24202112222404134401 |
6 | 312550533141515133 |
7 | 14404443261560562 |
oct | 1440272370322241 |
9 | 235660163880603 |
10 | 55000611005601 |
11 | 165856a0060158 |
12 | 62035a1412aa9 |
13 | 248c6c6267301 |
14 | d820881a0169 |
15 | 655a5ad24ed6 |
hex | 3205d3e1a4a1 |
55000611005601 has 32 divisors (see below), whose sum is σ = 81539994187008. Its totient is φ = 32799491112960.
The previous prime is 55000611005573. The next prime is 55000611005603. The reversal of 55000611005601 is 10650011600055.
It is not a de Polignac number, because 55000611005601 - 214 = 55000610989217 is a prime.
It is not an unprimeable number, because it can be changed into a prime (55000611005603) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 149143360 + ... + 149511681.
It is an arithmetic number, because the mean of its divisors is an integer number (2548124818344).
Almost surely, 255000611005601 is an apocalyptic number.
55000611005601 is a gapful number since it is divisible by the number (51) formed by its first and last digit.
It is an amenable number.
55000611005601 is a deficient number, since it is larger than the sum of its proper divisors (26539383181407).
55000611005601 is a wasteful number, since it uses less digits than its factorization.
55000611005601 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 298655241.
The product of its (nonzero) digits is 4500, while the sum is 30.
Adding to 55000611005601 its reverse (10650011600055), we get a palindrome (65650622605656).
The spelling of 55000611005601 in words is "fifty-five trillion, six hundred eleven million, five thousand, six hundred one".
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