Base | Representation |
---|---|
bin | 110011001110010100… |
… | …001010010101001011 |
3 | 12020222010002020220001 |
4 | 303032110022111023 |
5 | 1400120223433433 |
6 | 41133410143431 |
7 | 3654655531321 |
oct | 631624122513 |
9 | 166863066801 |
10 | 55000999243 |
11 | 213646a2883 |
12 | a7ab881b77 |
13 | 5256b8b388 |
14 | 293a9b1d11 |
15 | 166d94757d |
hex | cce50a54b |
55000999243 has 2 divisors, whose sum is σ = 55000999244. Its totient is φ = 55000999242.
The previous prime is 55000999187. The next prime is 55000999247. The reversal of 55000999243 is 34299900055.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55000999243 - 217 = 55000868171 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55000999193 and 55000999202.
It is not a weakly prime, because it can be changed into another prime (55000999247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27500499621 + 27500499622.
It is an arithmetic number, because the mean of its divisors is an integer number (27500499622).
Almost surely, 255000999243 is an apocalyptic number.
55000999243 is a deficient number, since it is larger than the sum of its proper divisors (1).
55000999243 is an equidigital number, since it uses as much as digits as its factorization.
55000999243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 437400, while the sum is 46.
The spelling of 55000999243 in words is "fifty-five billion, nine hundred ninety-nine thousand, two hundred forty-three".
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