Base | Representation |
---|---|
bin | 110011001110010100… |
… | …001100111101111001 |
3 | 12020222010002210200222 |
4 | 303032110030331321 |
5 | 1400120224310131 |
6 | 41133410305425 |
7 | 3654655604645 |
oct | 631624147571 |
9 | 166863083628 |
10 | 55001010041 |
11 | 213646aa9aa |
12 | a7ab888275 |
13 | 5256b93273 |
14 | 293a9b5c25 |
15 | 166d94a87b |
hex | cce50cf79 |
55001010041 has 2 divisors, whose sum is σ = 55001010042. Its totient is φ = 55001010040.
The previous prime is 55001009977. The next prime is 55001010151. The reversal of 55001010041 is 14001010055.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52359050041 + 2641960000 = 228821^2 + 51400^2 .
It is a cyclic number.
It is not a de Polignac number, because 55001010041 - 26 = 55001009977 is a prime.
It is a super-2 number, since 2×550010100412 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (55001010541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27500505020 + 27500505021.
It is an arithmetic number, because the mean of its divisors is an integer number (27500505021).
Almost surely, 255001010041 is an apocalyptic number.
It is an amenable number.
55001010041 is a deficient number, since it is larger than the sum of its proper divisors (1).
55001010041 is an equidigital number, since it uses as much as digits as its factorization.
55001010041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 100, while the sum is 17.
Adding to 55001010041 its reverse (14001010055), we get a palindrome (69002020096).
The spelling of 55001010041 in words is "fifty-five billion, one million, ten thousand, forty-one".
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