Base | Representation |
---|---|
bin | 110011001110010100… |
… | …010010001011110001 |
3 | 12020222010010220000101 |
4 | 303032110102023301 |
5 | 1400120231001114 |
6 | 41133410552401 |
7 | 3654656024152 |
oct | 631624221361 |
9 | 166863126011 |
10 | 55001031409 |
11 | 21364714a65 |
12 | a7ab898701 |
13 | 5256b9cbcc |
14 | 293a9bd929 |
15 | 166d951d74 |
hex | cce5122f1 |
55001031409 has 2 divisors, whose sum is σ = 55001031410. Its totient is φ = 55001031408.
The previous prime is 55001031403. The next prime is 55001031467. The reversal of 55001031409 is 90413010055.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 39251534400 + 15749497009 = 198120^2 + 125497^2 .
It is a cyclic number.
It is not a de Polignac number, because 55001031409 - 217 = 55000900337 is a prime.
It is a super-2 number, since 2×550010314092 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (55001031403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27500515704 + 27500515705.
It is an arithmetic number, because the mean of its divisors is an integer number (27500515705).
Almost surely, 255001031409 is an apocalyptic number.
It is an amenable number.
55001031409 is a deficient number, since it is larger than the sum of its proper divisors (1).
55001031409 is an equidigital number, since it uses as much as digits as its factorization.
55001031409 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2700, while the sum is 28.
The spelling of 55001031409 in words is "fifty-five billion, one million, thirty-one thousand, four hundred nine".
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