Base | Representation |
---|---|
bin | 101000000001010001110… |
… | …1111011111100010010001 |
3 | 201110211020201202102021010 |
4 | 1100002203233133202101 |
5 | 1210104111122300100 |
6 | 15410445542521133 |
7 | 1105245456301251 |
oct | 120024357374221 |
9 | 21424221672233 |
10 | 5500305275025 |
11 | 1830736a31670 |
12 | 749bb51361a9 |
13 | 30b8a4538b42 |
14 | 150305353961 |
15 | 98120056750 |
hex | 500a3bdf891 |
5500305275025 has 48 divisors (see below), whose sum is σ = 10188673651008. Its totient is φ = 2594738592000.
The previous prime is 5500305275011. The next prime is 5500305275027. The reversal of 5500305275025 is 5205725030055.
It is not a de Polignac number, because 5500305275025 - 211 = 5500305272977 is a prime.
It is a super-3 number, since 3×55003052750253 (a number of 39 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (5500305275027) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 90064566 + ... + 90125615.
It is an arithmetic number, because the mean of its divisors is an integer number (212264034396).
Almost surely, 25500305275025 is an apocalyptic number.
5500305275025 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
5500305275025 is a deficient number, since it is larger than the sum of its proper divisors (4688368375983).
5500305275025 is a wasteful number, since it uses less digits than its factorization.
5500305275025 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 180190242 (or 180190237 counting only the distinct ones).
The product of its (nonzero) digits is 262500, while the sum is 39.
The spelling of 5500305275025 in words is "five trillion, five hundred billion, three hundred five million, two hundred seventy-five thousand, twenty-five".
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